Voided Check Template

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It shows is_convertible is false from string_view to string.however, looking at how the stl does it in the header, they define a template typedef (of type _stringviewish) using _is_string_view_ish = enable_if_t<conjunction_v<is_convertiable<const _stringviewish&, basic_string_view<_elem, _traits>>, negation<is_convertable<const _stringviewish&, const. Was wondering if it's possible to have a template function that can branch depending on whether the type is derived from a particular.

17 Voided Check Templates [Free] TemplateArchive

You can use overloading, but if a large part of the code would work for any type, you might consider extracting the differing part into a separate function and overload that. Hmm because i had a large portion of same code until the 'specification' part. To add to those answers, the specification says (c++11 §8.3.5[dcl.func]/4): I'm trying to detect whether.

17 Voided Check Templates [Free] TemplateArchive

Jessen already mentioned in the comments , you have to look this oid up in your ad to get the template name. Compare vartype and typeid().name / typename. Template &lt;typename target_type, typename start_function_type, typename end_function_type&gt; Hmm because i had a large portion of same code until the 'specification' part. // should return true istemplate();

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Like someone mentioned the main logic can be done in a different function, which accepts an extra flag to indicate the type, and this specialized declaration can just set the flag accordingly and directly pass on all the other arguments without touching anything. Was wondering if it's possible to have a template function that can branch depending on whether the.

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I need a way to check if a templated class's type is void. It does contain the extension certificate template information though, but i cannot parse a name from it, because it does only contain the oid of the template. @gmannickg it's item 66 of sutter & alexandrescu's coding standards: You can use overloading, but if a large part of.

Voided Check Template - Here's roughly what i'm thinking: Template &lt;typename target_type, typename start_function_type, typename end_function_type&gt; Like someone mentioned the main logic can be done in a different function, which accepts an extra flag to indicate the type, and this specialized declaration can just set the flag accordingly and directly pass on all the other arguments without touching anything. @gmannickg it's item 66 of sutter & alexandrescu's coding standards: I'm trying to detect whether a type (or more precisely, an identifier as technically a template is not a type) is a template or not, eg to have a function istemplate which behaves the following way: I need a way to check if a templated class's type is void.

@gmannickg it's item 66 of sutter & alexandrescu's coding standards: // should return true istemplate(); Here's roughly what i'm thinking: Jessen already mentioned in the comments , you have to look this oid up in your ad to get the template name. It does contain the extension certificate template information though, but i cannot parse a name from it, because it does only contain the oid of the template.

If You're Writing A Function Template, Prefer To Write It As A Single Function Template That Should Never Be Specialized Or Overloaded, And Implement The Function Template Entirely In Terms Of A.

It shows is_convertible is false from string_view to string.however, looking at how the stl does it in the header, they define a template typedef (of type _stringviewish) using _is_string_view_ish = enable_if_t<conjunction_v<is_convertiable<const _stringviewish&, basic_string_view<_elem, _traits>>, negation<is_convertable<const _stringviewish&, const. I'm trying to detect whether a type (or more precisely, an identifier as technically a template is not a type) is a template or not, eg to have a function istemplate which behaves the following way: I need a way to check if a templated class's type is void. // should return true istemplate();

@Gmannickg It's Item 66 Of Sutter & Alexandrescu's Coding Standards:

Several answers already explain the rationale. Like someone mentioned the main logic can be done in a different function, which accepts an extra flag to indicate the type, and this specialized declaration can just set the flag accordingly and directly pass on all the other arguments without touching anything. Template <typename target_type, typename start_function_type, typename end_function_type> Was wondering if it's possible to have a template function that can branch depending on whether the type is derived from a particular class.

Jessen Already Mentioned In The Comments , You Have To Look This Oid Up In Your Ad To Get The Template Name.

This really sounds like a good idea though, if someone doesn't want to use type_traits. How to check if template type is of another template type? It does contain the extension certificate template information though, but i cannot parse a name from it, because it does only contain the oid of the template. Here's roughly what i'm thinking:

To Add To Those Answers, The Specification Says (C++11 §8.3.5[Dcl.func]/4):

Hmm because i had a large portion of same code until the 'specification' part. Compare vartype and typeid().name / typename. You can use overloading, but if a large part of the code would work for any type, you might consider extracting the differing part into a separate function and overload that.